Reds’ Miley throws no-hitter against Indians


The Indians were no-hit Friday night by Cincinnati's Wade Miley

Cincinnati Reds teammates mob Wade Miley, center, after he pitched a no-hitter against the Cleveland Indians in a baseball game, Friday, May 7, 2021, in Cleveland. (AP Photo/Tony Dejak)

CLEVELAND, Ohio (WKBN) – Cincinnati Reds’ pitcher Wade Miley tossed a no-hitter Friday night in a 3-0 win over the Cleveland Indians.

It is the fourth no-hitter in baseball this season, and the second in three days.

Miley went the distance, allowing just one walk with eight strikeouts.

A scoreless tie was broken up in the ninth inning, when Emmanuel Clase allowed three hits and three runs (2 earned).

Zach Plesac tossed eight shutout innings for Cleveland, allowing just three hits with seven strikeouts on the night.

It is the second time in a month that the Indians were no-hit, with the first coming back on April 14 at Chicago.

Friday’s no-hitter was the 15th in Cleveland franchise history, with two coming as the Cleveland Blue, two as the Cleveland Naps, and eleven as the Indians.

The Indians are now the 17th team all-time to be no-hit twice in the same season. The last no-hitter thrown at Progressive Field was in 2011, when Ervin Santana no-hit the Tribe while playing for the Los Angeles Angels.

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